(4y-3)/(y^2+1)=4/y

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Solution for (4y-3)/(y^2+1)=4/y equation: 



(4y-3)/(y^2+1)=4/y

We move all terms to the left:

(4y-3)/(y^2+1)-(4/y)=0



Domain of the equation: (y^2+1)!=0

We move all terms containing y to the left, all other terms to the right

y^2!=-1

y^2!=-1/

y^2!=√-1/

y!=NAN

y∈R





Domain of the equation: y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(4y-3)/(y^2+1)-(+4/y)=0

We get rid of parentheses

(4y-3)/(y^2+1)-4/y=0

We calculate fractions

We do not support eypression: y^3

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